af20ca7478
Motivated by the distutils removal, this replaces version parsing by a "good enough" version comparison algorithm...
68 lines
2 KiB
Python
68 lines
2 KiB
Python
# SPDX-License-Identifier: MIT
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# SPDX-FileCopyrightText: © 2004 Tristan Seligmann and Jonathan Jacobs
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# SPDX-FileCopyrightText: © 2012 Bastian Kleineidam
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# SPDX-FileCopyrightText: © 2015 Tobias Gruetzmacher
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import os
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import re
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from typing import Any
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import dosagelib
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from . import http
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UPDATE_URL = 'https://api.github.com/repos/webcomics/dosage/releases/latest'
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EXTPRIO = {
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'.exe': 1 if os.name == 'nt' else 9,
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'.whl': 2,
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'.gz': 3,
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}
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def check_update() -> None | tuple[str, None | str]:
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"""Return the following values:
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throws exception - online version could not be determined
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None - user has newest version
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(version, url string) - update available
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(version, None) - current version is newer than online version
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"""
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version, value = get_online_version()
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if version == dosagelib.__version__:
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# user has newest version
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return None
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if is_newer_version(version):
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# value is an URL linking to the update package
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return (version, value)
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# user is running a local or development version
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return (version, None)
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def asset_key(asset: dict[str, Any]) -> int:
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return EXTPRIO.get(os.path.splitext(asset['browser_download_url'])[1], 99)
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def get_online_version() -> tuple[str, None | str]:
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"""Download update info and parse it."""
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response = http.default_session.get(UPDATE_URL)
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response.raise_for_status()
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page = response.json()
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version = page['tag_name']
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url = None
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try:
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assets = sorted(page['assets'], key=asset_key)
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if len(assets) > 0:
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url = assets[0]['browser_download_url']
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except KeyError:
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pass
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return version, url
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def version_nums(ver: str) -> tuple[int, ...]:
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"""Extract all numeric "sub-parts" of a version string. Not very exact, but
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works for our use case."""
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return tuple(int(s) for s in re.split(r'\D+', ver + '0'))
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def is_newer_version(version) -> bool:
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"""Check if given version is newer than current version."""
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return version_nums(version) > version_nums(dosagelib.__version__)
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